(3x^2-x+1)+(x)=0

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Solution for (3x^2-x+1)+(x)=0 equation:


Simplifying
(3x2 + -1x + 1) + (x) = 0

Reorder the terms:
(1 + -1x + 3x2) + (x) = 0

Remove parenthesis around (1 + -1x + 3x2)
1 + -1x + 3x2 + (x) = 0
1 + -1x + 3x2 + x = 0

Reorder the terms:
1 + -1x + x + 3x2 = 0

Combine like terms: -1x + x = 0
1 + 0 + 3x2 = 0
1 + 3x2 = 0

Solving
1 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3x2 = 0 + -1
3x2 = 0 + -1

Combine like terms: 0 + -1 = -1
3x2 = -1

Divide each side by '3'.
x2 = -0.3333333333

Simplifying
x2 = -0.3333333333

Reorder the terms:
0.3333333333 + x2 = -0.3333333333 + 0.3333333333

Combine like terms: -0.3333333333 + 0.3333333333 = 0.0000000000
0.3333333333 + x2 = 0.0000000000

The solution to this equation could not be determined.

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